2(6z+1)-6=68

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Solution for 2(6z+1)-6=68 equation: 



2(6z+1)-6=68

We move all terms to the left:

2(6z+1)-6-(68)=0

We add all the numbers together, and all the variables

2(6z+1)-74=0

We multiply parentheses

12z+2-74=0

We add all the numbers together, and all the variables

12z-72=0

We move all terms containing z to the left, all other terms to the right

12z=72

z=72/12

z=6

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