2(6z+10)=-3z+77+19z-97

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Solution for 2(6z+10)=-3z+77+19z-97 equation: 



2(6z+10)=-3z+77+19z-97

We move all terms to the left:

2(6z+10)-(-3z+77+19z-97)=0

We add all the numbers together, and all the variables

2(6z+10)-(16z-20)=0

We multiply parentheses

12z-(16z-20)+20=0

We get rid of parentheses

12z-16z+20+20=0

We add all the numbers together, and all the variables

-4z+40=0

We move all terms containing z to the left, all other terms to the right

-4z=-40

z=-40/-4

z=+10

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