2(6z-1)-3(z+1)=4(z+1)

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Solution for 2(6z-1)-3(z+1)=4(z+1) equation:


Simplifying
2(6z + -1) + -3(z + 1) = 4(z + 1)

Reorder the terms:
2(-1 + 6z) + -3(z + 1) = 4(z + 1)
(-1 * 2 + 6z * 2) + -3(z + 1) = 4(z + 1)
(-2 + 12z) + -3(z + 1) = 4(z + 1)

Reorder the terms:
-2 + 12z + -3(1 + z) = 4(z + 1)
-2 + 12z + (1 * -3 + z * -3) = 4(z + 1)
-2 + 12z + (-3 + -3z) = 4(z + 1)

Reorder the terms:
-2 + -3 + 12z + -3z = 4(z + 1)

Combine like terms: -2 + -3 = -5
-5 + 12z + -3z = 4(z + 1)

Combine like terms: 12z + -3z = 9z
-5 + 9z = 4(z + 1)

Reorder the terms:
-5 + 9z = 4(1 + z)
-5 + 9z = (1 * 4 + z * 4)
-5 + 9z = (4 + 4z)

Solving
-5 + 9z = 4 + 4z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-4z' to each side of the equation.
-5 + 9z + -4z = 4 + 4z + -4z

Combine like terms: 9z + -4z = 5z
-5 + 5z = 4 + 4z + -4z

Combine like terms: 4z + -4z = 0
-5 + 5z = 4 + 0
-5 + 5z = 4

Add '5' to each side of the equation.
-5 + 5 + 5z = 4 + 5

Combine like terms: -5 + 5 = 0
0 + 5z = 4 + 5
5z = 4 + 5

Combine like terms: 4 + 5 = 9
5z = 9

Divide each side by '5'.
z = 1.8

Simplifying
z = 1.8

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