2(6z-1)-5(z+1)=2(z+1)

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Solution for 2(6z-1)-5(z+1)=2(z+1) equation:


Simplifying
2(6z + -1) + -5(z + 1) = 2(z + 1)

Reorder the terms:
2(-1 + 6z) + -5(z + 1) = 2(z + 1)
(-1 * 2 + 6z * 2) + -5(z + 1) = 2(z + 1)
(-2 + 12z) + -5(z + 1) = 2(z + 1)

Reorder the terms:
-2 + 12z + -5(1 + z) = 2(z + 1)
-2 + 12z + (1 * -5 + z * -5) = 2(z + 1)
-2 + 12z + (-5 + -5z) = 2(z + 1)

Reorder the terms:
-2 + -5 + 12z + -5z = 2(z + 1)

Combine like terms: -2 + -5 = -7
-7 + 12z + -5z = 2(z + 1)

Combine like terms: 12z + -5z = 7z
-7 + 7z = 2(z + 1)

Reorder the terms:
-7 + 7z = 2(1 + z)
-7 + 7z = (1 * 2 + z * 2)
-7 + 7z = (2 + 2z)

Solving
-7 + 7z = 2 + 2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-2z' to each side of the equation.
-7 + 7z + -2z = 2 + 2z + -2z

Combine like terms: 7z + -2z = 5z
-7 + 5z = 2 + 2z + -2z

Combine like terms: 2z + -2z = 0
-7 + 5z = 2 + 0
-7 + 5z = 2

Add '7' to each side of the equation.
-7 + 7 + 5z = 2 + 7

Combine like terms: -7 + 7 = 0
0 + 5z = 2 + 7
5z = 2 + 7

Combine like terms: 2 + 7 = 9
5z = 9

Divide each side by '5'.
z = 1.8

Simplifying
z = 1.8

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