2(6z-1)-5(z+4)=2(z+1)

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Solution for 2(6z-1)-5(z+4)=2(z+1) equation:


Simplifying
2(6z + -1) + -5(z + 4) = 2(z + 1)

Reorder the terms:
2(-1 + 6z) + -5(z + 4) = 2(z + 1)
(-1 * 2 + 6z * 2) + -5(z + 4) = 2(z + 1)
(-2 + 12z) + -5(z + 4) = 2(z + 1)

Reorder the terms:
-2 + 12z + -5(4 + z) = 2(z + 1)
-2 + 12z + (4 * -5 + z * -5) = 2(z + 1)
-2 + 12z + (-20 + -5z) = 2(z + 1)

Reorder the terms:
-2 + -20 + 12z + -5z = 2(z + 1)

Combine like terms: -2 + -20 = -22
-22 + 12z + -5z = 2(z + 1)

Combine like terms: 12z + -5z = 7z
-22 + 7z = 2(z + 1)

Reorder the terms:
-22 + 7z = 2(1 + z)
-22 + 7z = (1 * 2 + z * 2)
-22 + 7z = (2 + 2z)

Solving
-22 + 7z = 2 + 2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-2z' to each side of the equation.
-22 + 7z + -2z = 2 + 2z + -2z

Combine like terms: 7z + -2z = 5z
-22 + 5z = 2 + 2z + -2z

Combine like terms: 2z + -2z = 0
-22 + 5z = 2 + 0
-22 + 5z = 2

Add '22' to each side of the equation.
-22 + 22 + 5z = 2 + 22

Combine like terms: -22 + 22 = 0
0 + 5z = 2 + 22
5z = 2 + 22

Combine like terms: 2 + 22 = 24
5z = 24

Divide each side by '5'.
z = 4.8

Simplifying
z = 4.8

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