2(6z-1)-5(z+4)=5(z+1)

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Solution for 2(6z-1)-5(z+4)=5(z+1) equation:


Simplifying
2(6z + -1) + -5(z + 4) = 5(z + 1)

Reorder the terms:
2(-1 + 6z) + -5(z + 4) = 5(z + 1)
(-1 * 2 + 6z * 2) + -5(z + 4) = 5(z + 1)
(-2 + 12z) + -5(z + 4) = 5(z + 1)

Reorder the terms:
-2 + 12z + -5(4 + z) = 5(z + 1)
-2 + 12z + (4 * -5 + z * -5) = 5(z + 1)
-2 + 12z + (-20 + -5z) = 5(z + 1)

Reorder the terms:
-2 + -20 + 12z + -5z = 5(z + 1)

Combine like terms: -2 + -20 = -22
-22 + 12z + -5z = 5(z + 1)

Combine like terms: 12z + -5z = 7z
-22 + 7z = 5(z + 1)

Reorder the terms:
-22 + 7z = 5(1 + z)
-22 + 7z = (1 * 5 + z * 5)
-22 + 7z = (5 + 5z)

Solving
-22 + 7z = 5 + 5z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-5z' to each side of the equation.
-22 + 7z + -5z = 5 + 5z + -5z

Combine like terms: 7z + -5z = 2z
-22 + 2z = 5 + 5z + -5z

Combine like terms: 5z + -5z = 0
-22 + 2z = 5 + 0
-22 + 2z = 5

Add '22' to each side of the equation.
-22 + 22 + 2z = 5 + 22

Combine like terms: -22 + 22 = 0
0 + 2z = 5 + 22
2z = 5 + 22

Combine like terms: 5 + 22 = 27
2z = 27

Divide each side by '2'.
z = 13.5

Simplifying
z = 13.5

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