2(6z-1)=3(4z+2)

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Solution for 2(6z-1)=3(4z+2) equation: 



2(6z-1)=3(4z+2)

We move all terms to the left:

2(6z-1)-(3(4z+2))=0

We multiply parentheses

12z-(3(4z+2))-2=0



We calculate terms in parentheses: -(3(4z+2)), so:

3(4z+2)

We multiply parentheses

12z+6

Back to the equation:

-(12z+6)



We get rid of parentheses

12z-12z-6-2=0

We add all the numbers together, and all the variables

-8!=0

There is no solution for this equation

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