2(6z-2)=33

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Solution for 2(6z-2)=33 equation: 



2(6z-2)=33

We move all terms to the left:

2(6z-2)-(33)=0

We multiply parentheses

12z-4-33=0

We add all the numbers together, and all the variables

12z-37=0

We move all terms containing z to the left, all other terms to the right

12z=37

z=37/12

z=3+1/12

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