2(7+4x)=-3(3x-1)+11

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Solution for 2(7+4x)=-3(3x-1)+11 equation: 



2(7+4x)=-3(3x-1)+11

We move all terms to the left:

2(7+4x)-(-3(3x-1)+11)=0

We add all the numbers together, and all the variables

2(4x+7)-(-3(3x-1)+11)=0

We multiply parentheses

8x-(-3(3x-1)+11)+14=0



We calculate terms in parentheses: -(-3(3x-1)+11), so:

-3(3x-1)+11

We multiply parentheses

-9x+3+11

We add all the numbers together, and all the variables

-9x+14

Back to the equation:

-(-9x+14)



We get rid of parentheses

8x+9x-14+14=0

We add all the numbers together, and all the variables

17x=0

x=0/17

x=0

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