2(7+5b)=2(b-5)

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Solution for 2(7+5b)=2(b-5) equation: 



2(7+5b)=2(b-5)

We move all terms to the left:

2(7+5b)-(2(b-5))=0

We add all the numbers together, and all the variables

2(5b+7)-(2(b-5))=0

We multiply parentheses

10b-(2(b-5))+14=0



We calculate terms in parentheses: -(2(b-5)), so:

2(b-5)

We multiply parentheses

2b-10

Back to the equation:

-(2b-10)



We get rid of parentheses

10b-2b+10+14=0

We add all the numbers together, and all the variables

8b+24=0

We move all terms containing b to the left, all other terms to the right

8b=-24

b=-24/8

b=-3

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