2(7-2x)=3(3x-2)-4

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Solution for 2(7-2x)=3(3x-2)-4 equation: 



2(7-2x)=3(3x-2)-4

We move all terms to the left:

2(7-2x)-(3(3x-2)-4)=0

We add all the numbers together, and all the variables

2(-2x+7)-(3(3x-2)-4)=0

We multiply parentheses

-4x-(3(3x-2)-4)+14=0



We calculate terms in parentheses: -(3(3x-2)-4), so:

3(3x-2)-4

We multiply parentheses

9x-6-4

We add all the numbers together, and all the variables

9x-10

Back to the equation:

-(9x-10)



We get rid of parentheses

-4x-9x+10+14=0

We add all the numbers together, and all the variables

-13x+24=0

We move all terms containing x to the left, all other terms to the right

-13x=-24

x=-24/-13

x=1+11/13

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