2(7-2z)=2(z+5)

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Solution for 2(7-2z)=2(z+5) equation:



2(7-2z)=2(z+5)
We move all terms to the left:
2(7-2z)-(2(z+5))=0
We add all the numbers together, and all the variables
2(-2z+7)-(2(z+5))=0
We multiply parentheses
-4z-(2(z+5))+14=0
We calculate terms in parentheses: -(2(z+5)), so:
2(z+5)
We multiply parentheses
2z+10
Back to the equation:
-(2z+10)
We get rid of parentheses
-4z-2z-10+14=0
We add all the numbers together, and all the variables
-6z+4=0
We move all terms containing z to the left, all other terms to the right
-6z=-4
z=-4/-6
z=2/3

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