2(7-3z)=2(10-5z)

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Solution for 2(7-3z)=2(10-5z) equation: 



2(7-3z)=2(10-5z)

We move all terms to the left:

2(7-3z)-(2(10-5z))=0

We add all the numbers together, and all the variables

2(-3z+7)-(2(-5z+10))=0

We multiply parentheses

-6z-(2(-5z+10))+14=0



We calculate terms in parentheses: -(2(-5z+10)), so:

2(-5z+10)

We multiply parentheses

-10z+20

Back to the equation:

-(-10z+20)



We get rid of parentheses

-6z+10z-20+14=0

We add all the numbers together, and all the variables

4z-6=0

We move all terms containing z to the left, all other terms to the right

4z=6

z=6/4

z=1+1/2

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