2(7-4x)-(2x-3)=1-2(x+1)

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Solution for 2(7-4x)-(2x-3)=1-2(x+1) equation: 



2(7-4x)-(2x-3)=1-2(x+1)

We move all terms to the left:

2(7-4x)-(2x-3)-(1-2(x+1))=0

We add all the numbers together, and all the variables

2(-4x+7)-(2x-3)-(1-2(x+1))=0

We multiply parentheses

-8x-(2x-3)-(1-2(x+1))+14=0

We get rid of parentheses

-8x-2x-(1-2(x+1))+3+14=0



We calculate terms in parentheses: -(1-2(x+1)), so:

1-2(x+1)

determiningTheFunctionDomain
-2(x+1)+1

We multiply parentheses

-2x-2+1

We add all the numbers together, and all the variables

-2x-1

Back to the equation:

-(-2x-1)



We add all the numbers together, and all the variables

-10x-(-2x-1)+17=0

We get rid of parentheses

-10x+2x+1+17=0

We add all the numbers together, and all the variables

-8x+18=0

We move all terms containing x to the left, all other terms to the right

-8x=-18

x=-18/-8

x=2+1/4

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