2(7-4x)=8-(x+5)

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Solution for 2(7-4x)=8-(x+5) equation:



2(7-4x)=8-(x+5)
We move all terms to the left:
2(7-4x)-(8-(x+5))=0
We add all the numbers together, and all the variables
2(-4x+7)-(8-(x+5))=0
We multiply parentheses
-8x-(8-(x+5))+14=0
We calculate terms in parentheses: -(8-(x+5)), so:
8-(x+5)
determiningTheFunctionDomain -(x+5)+8
We get rid of parentheses
-x-5+8
We add all the numbers together, and all the variables
-1x+3
Back to the equation:
-(-1x+3)
We get rid of parentheses
-8x+1x-3+14=0
We add all the numbers together, and all the variables
-7x+11=0
We move all terms containing x to the left, all other terms to the right
-7x=-11
x=-11/-7
x=1+4/7

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