2(7-8b)=32-10b

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Solution for 2(7-8b)=32-10b equation:



2(7-8b)=32-10b
We move all terms to the left:
2(7-8b)-(32-10b)=0
We add all the numbers together, and all the variables
2(-8b+7)-(-10b+32)=0
We multiply parentheses
-16b-(-10b+32)+14=0
We get rid of parentheses
-16b+10b-32+14=0
We add all the numbers together, and all the variables
-6b-18=0
We move all terms containing b to the left, all other terms to the right
-6b=18
b=18/-6
b=-3

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