2(7-j)=6(1+2j)+3

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Solution for 2(7-j)=6(1+2j)+3 equation: 



2(7-j)=6(1+2j)+3

We move all terms to the left:

2(7-j)-(6(1+2j)+3)=0

We add all the numbers together, and all the variables

2(-1j+7)-(6(2j+1)+3)=0

We multiply parentheses

-2j-(6(2j+1)+3)+14=0



We calculate terms in parentheses: -(6(2j+1)+3), so:

6(2j+1)+3

We multiply parentheses

12j+6+3

We add all the numbers together, and all the variables

12j+9

Back to the equation:

-(12j+9)



We get rid of parentheses

-2j-12j-9+14=0

We add all the numbers together, and all the variables

-14j+5=0

We move all terms containing j to the left, all other terms to the right

-14j=-5

j=-5/-14

j=5/14

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