2(72+x)=3(-x+28)

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Solution for 2(72+x)=3(-x+28) equation: 



2(72+x)=3(-x+28)

We move all terms to the left:

2(72+x)-(3(-x+28))=0

We add all the numbers together, and all the variables

2(x+72)-(3(-1x+28))=0

We multiply parentheses

2x-(3(-1x+28))+144=0



We calculate terms in parentheses: -(3(-1x+28)), so:

3(-1x+28)

We multiply parentheses

-3x+84

Back to the equation:

-(-3x+84)



We get rid of parentheses

2x+3x-84+144=0

We add all the numbers together, and all the variables

5x+60=0

We move all terms containing x to the left, all other terms to the right

5x=-60

x=-60/5

x=-12

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