2(78+6x)=67-4x

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Solution for 2(78+6x)=67-4x equation: 



2(78+6x)=67-4x

We move all terms to the left:

2(78+6x)-(67-4x)=0

We add all the numbers together, and all the variables

2(6x+78)-(-4x+67)=0

We multiply parentheses

12x-(-4x+67)+156=0

We get rid of parentheses

12x+4x-67+156=0

We add all the numbers together, and all the variables

16x+89=0

We move all terms containing x to the left, all other terms to the right

16x=-89

x=-89/16

x=-5+9/16

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