2(7c+8)-3(3c-5)=-19

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Solution for 2(7c+8)-3(3c-5)=-19 equation: 



2(7c+8)-3(3c-5)=-19

We move all terms to the left:

2(7c+8)-3(3c-5)-(-19)=0

We add all the numbers together, and all the variables

2(7c+8)-3(3c-5)+19=0

We multiply parentheses

14c-9c+16+15+19=0

We add all the numbers together, and all the variables

5c+50=0

We move all terms containing c to the left, all other terms to the right

5c=-50

c=-50/5

c=-10

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