2(7f-4)=5+3(1+2f)

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Solution for 2(7f-4)=5+3(1+2f) equation: 



2(7f-4)=5+3(1+2f)

We move all terms to the left:

2(7f-4)-(5+3(1+2f))=0

We add all the numbers together, and all the variables

2(7f-4)-(5+3(2f+1))=0

We multiply parentheses

14f-(5+3(2f+1))-8=0



We calculate terms in parentheses: -(5+3(2f+1)), so:

5+3(2f+1)

determiningTheFunctionDomain
3(2f+1)+5

We multiply parentheses

6f+3+5

We add all the numbers together, and all the variables

6f+8

Back to the equation:

-(6f+8)



We get rid of parentheses

14f-6f-8-8=0

We add all the numbers together, and all the variables

8f-16=0

We move all terms containing f to the left, all other terms to the right

8f=16

f=16/8

f=2

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