2(7n+2)=5(1+3n)-5

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Solution for 2(7n+2)=5(1+3n)-5 equation: 



2(7n+2)=5(1+3n)-5

We move all terms to the left:

2(7n+2)-(5(1+3n)-5)=0

We add all the numbers together, and all the variables

2(7n+2)-(5(3n+1)-5)=0

We multiply parentheses

14n-(5(3n+1)-5)+4=0



We calculate terms in parentheses: -(5(3n+1)-5), so:

5(3n+1)-5

We multiply parentheses

15n+5-5

We add all the numbers together, and all the variables

15n

Back to the equation:

-(15n)



We add all the numbers together, and all the variables

-1n+4=0

We move all terms containing n to the left, all other terms to the right

-n=-4

n=-4/-1

n=+4

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