2(7q-3)=2(6q+11)

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Solution for 2(7q-3)=2(6q+11) equation: 



2(7q-3)=2(6q+11)

We move all terms to the left:

2(7q-3)-(2(6q+11))=0

We multiply parentheses

14q-(2(6q+11))-6=0



We calculate terms in parentheses: -(2(6q+11)), so:

2(6q+11)

We multiply parentheses

12q+22

Back to the equation:

-(12q+22)



We get rid of parentheses

14q-12q-22-6=0

We add all the numbers together, and all the variables

2q-28=0

We move all terms containing q to the left, all other terms to the right

2q=28

q=28/2

q=14

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