2(7w+1)=3(w+4)

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Solution for 2(7w+1)=3(w+4) equation: 



2(7w+1)=3(w+4)

We move all terms to the left:

2(7w+1)-(3(w+4))=0

We multiply parentheses

14w-(3(w+4))+2=0



We calculate terms in parentheses: -(3(w+4)), so:

3(w+4)

We multiply parentheses

3w+12

Back to the equation:

-(3w+12)



We get rid of parentheses

14w-3w-12+2=0

We add all the numbers together, and all the variables

11w-10=0

We move all terms containing w to the left, all other terms to the right

11w=10

w=10/11

w=10/11

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