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2(7x+1)+5x=20x-(x-2)
We move all terms to the left:
2(7x+1)+5x-(20x-(x-2))=0
We add all the numbers together, and all the variables
5x+2(7x+1)-(20x-(x-2))=0
We multiply parentheses
5x+14x-(20x-(x-2))+2=0
We calculate terms in parentheses: -(20x-(x-2)), so:We add all the numbers together, and all the variables
20x-(x-2)
We get rid of parentheses
20x-x+2
We add all the numbers together, and all the variables
19x+2
Back to the equation:
-(19x+2)
19x-(19x+2)+2=0
We get rid of parentheses
19x-19x-2+2=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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