2(7x+5)+20=2(3x-1)

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Solution for 2(7x+5)+20=2(3x-1) equation: 



2(7x+5)+20=2(3x-1)

We move all terms to the left:

2(7x+5)+20-(2(3x-1))=0

We multiply parentheses

14x-(2(3x-1))+10+20=0



We calculate terms in parentheses: -(2(3x-1)), so:

2(3x-1)

We multiply parentheses

6x-2

Back to the equation:

-(6x-2)



We add all the numbers together, and all the variables

14x-(6x-2)+30=0

We get rid of parentheses

14x-6x+2+30=0

We add all the numbers together, and all the variables

8x+32=0

We move all terms containing x to the left, all other terms to the right

8x=-32

x=-32/8

x=-4

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