2(7x-3)=4(7-2x)+5x

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Solution for 2(7x-3)=4(7-2x)+5x equation: 



2(7x-3)=4(7-2x)+5x

We move all terms to the left:

2(7x-3)-(4(7-2x)+5x)=0

We add all the numbers together, and all the variables

2(7x-3)-(4(-2x+7)+5x)=0

We multiply parentheses

14x-(4(-2x+7)+5x)-6=0



We calculate terms in parentheses: -(4(-2x+7)+5x), so:

4(-2x+7)+5x

We add all the numbers together, and all the variables

5x+4(-2x+7)

We multiply parentheses

5x-8x+28

We add all the numbers together, and all the variables

-3x+28

Back to the equation:

-(-3x+28)



We get rid of parentheses

14x+3x-28-6=0

We add all the numbers together, and all the variables

17x-34=0

We move all terms containing x to the left, all other terms to the right

17x=34

x=34/17

x=2

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