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2(7x-4)-4=2(x+5)
We move all terms to the left:
2(7x-4)-4-(2(x+5))=0
We multiply parentheses
14x-(2(x+5))-8-4=0
We calculate terms in parentheses: -(2(x+5)), so:We add all the numbers together, and all the variables
2(x+5)
We multiply parentheses
2x+10
Back to the equation:
-(2x+10)
14x-(2x+10)-12=0
We get rid of parentheses
14x-2x-10-12=0
We add all the numbers together, and all the variables
12x-22=0
We move all terms containing x to the left, all other terms to the right
12x=22
x=22/12
x=1+5/6
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