2(7x-4)=40+8x

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Solution for 2(7x-4)=40+8x equation: 



2(7x-4)=40+8x

We move all terms to the left:

2(7x-4)-(40+8x)=0

We add all the numbers together, and all the variables

2(7x-4)-(8x+40)=0

We multiply parentheses

14x-(8x+40)-8=0

We get rid of parentheses

14x-8x-40-8=0

We add all the numbers together, and all the variables

6x-48=0

We move all terms containing x to the left, all other terms to the right

6x=48

x=48/6

x=8

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