2(7x2)=38

Solution for 2(7x2)=38 equation:

2(7x^2)=38

We move all terms to the left:

2(7x^2)-(38)=0

a = 27; b = 0; c = -38;
Δ = b2-4ac
Δ = 02-4·27·(-38)
Δ = 4104
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4104}=\sqrt{36*114}=\sqrt{36}*\sqrt{114}=6\sqrt{114}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{114}}{2*27}=\frac{0-6\sqrt{114}}{54}
=-\frac{6\sqrt{114}}{54}
=-\frac{\sqrt{114}}{9}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{114}}{2*27}=\frac{0+6\sqrt{114}}{54}
=\frac{6\sqrt{114}}{54}
=\frac{\sqrt{114}}{9}
$