2(7y+1)=8(2y-10)

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Solution for 2(7y+1)=8(2y-10) equation: 



2(7y+1)=8(2y-10)

We move all terms to the left:

2(7y+1)-(8(2y-10))=0

We multiply parentheses

14y-(8(2y-10))+2=0



We calculate terms in parentheses: -(8(2y-10)), so:

8(2y-10)

We multiply parentheses

16y-80

Back to the equation:

-(16y-80)



We get rid of parentheses

14y-16y+80+2=0

We add all the numbers together, and all the variables

-2y+82=0

We move all terms containing y to the left, all other terms to the right

-2y=-82

y=-82/-2

y=+41

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