2(7z+4)=14z+2(z+12)

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Solution for 2(7z+4)=14z+2(z+12) equation:


Simplifying
2(7z + 4) = 14z + 2(z + 12)

Reorder the terms:
2(4 + 7z) = 14z + 2(z + 12)
(4 * 2 + 7z * 2) = 14z + 2(z + 12)
(8 + 14z) = 14z + 2(z + 12)

Reorder the terms:
8 + 14z = 14z + 2(12 + z)
8 + 14z = 14z + (12 * 2 + z * 2)
8 + 14z = 14z + (24 + 2z)

Reorder the terms:
8 + 14z = 24 + 14z + 2z

Combine like terms: 14z + 2z = 16z
8 + 14z = 24 + 16z

Solving
8 + 14z = 24 + 16z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-16z' to each side of the equation.
8 + 14z + -16z = 24 + 16z + -16z

Combine like terms: 14z + -16z = -2z
8 + -2z = 24 + 16z + -16z

Combine like terms: 16z + -16z = 0
8 + -2z = 24 + 0
8 + -2z = 24

Add '-8' to each side of the equation.
8 + -8 + -2z = 24 + -8

Combine like terms: 8 + -8 = 0
0 + -2z = 24 + -8
-2z = 24 + -8

Combine like terms: 24 + -8 = 16
-2z = 16

Divide each side by '-2'.
z = -8

Simplifying
z = -8

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