2(8-2z)-2(4z+9)=z-4

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Solution for 2(8-2z)-2(4z+9)=z-4 equation:



2(8-2z)-2(4z+9)=z-4
We move all terms to the left:
2(8-2z)-2(4z+9)-(z-4)=0
We add all the numbers together, and all the variables
2(-2z+8)-2(4z+9)-(z-4)=0
We multiply parentheses
-4z-8z-(z-4)+16-18=0
We get rid of parentheses
-4z-8z-z+4+16-18=0
We add all the numbers together, and all the variables
-13z+2=0
We move all terms containing z to the left, all other terms to the right
-13z=-2
z=-2/-13
z=2/13

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