2(8-4x)=1/3(33-18x)=3

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Solution for 2(8-4x)=1/3(33-18x)=3 equation: 



2(8-4x)=1/3(33-18x)=3

We move all terms to the left:

2(8-4x)-(1/3(33-18x))=0



Domain of the equation: 3(33-18x))!=0

x∈R



We add all the numbers together, and all the variables

2(-4x+8)-(1/3(-18x+33))=0

We multiply parentheses

-8x-(1/3(-18x+33))+16=0

We multiply all the terms by the denominator


-8x*3(-18x+33))-(1+16*3(-18x+33))=0

Wy multiply elements

-24x^2(-+48x(-=0

We use the square of the difference formula

-24x^2(-48x(-=0

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