2(8r+5)-3=4(4r-1)+11

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Solution for 2(8r+5)-3=4(4r-1)+11 equation: 


Simplifying
2(8r + 5) + -3 = 4(4r + -1) + 11

Reorder the terms:
2(5 + 8r) + -3 = 4(4r + -1) + 11
(5 * 2 + 8r * 2) + -3 = 4(4r + -1) + 11
(10 + 16r) + -3 = 4(4r + -1) + 11

Reorder the terms:
10 + -3 + 16r = 4(4r + -1) + 11

Combine like terms: 10 + -3 = 7
7 + 16r = 4(4r + -1) + 11

Reorder the terms:
7 + 16r = 4(-1 + 4r) + 11
7 + 16r = (-1 * 4 + 4r * 4) + 11
7 + 16r = (-4 + 16r) + 11

Reorder the terms:
7 + 16r = -4 + 11 + 16r

Combine like terms: -4 + 11 = 7
7 + 16r = 7 + 16r

Add '-7' to each side of the equation.
7 + -7 + 16r = 7 + -7 + 16r

Combine like terms: 7 + -7 = 0
0 + 16r = 7 + -7 + 16r
16r = 7 + -7 + 16r

Combine like terms: 7 + -7 = 0
16r = 0 + 16r
16r = 16r

Add '-16r' to each side of the equation.
16r + -16r = 16r + -16r

Combine like terms: 16r + -16r = 0
0 = 16r + -16r

Combine like terms: 16r + -16r = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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