2(8r-4)=5r+8(r-7)

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Solution for 2(8r-4)=5r+8(r-7) equation: 



2(8r-4)=5r+8(r-7)

We move all terms to the left:

2(8r-4)-(5r+8(r-7))=0

We multiply parentheses

16r-(5r+8(r-7))-8=0



We calculate terms in parentheses: -(5r+8(r-7)), so:

5r+8(r-7)

We multiply parentheses

5r+8r-56

We add all the numbers together, and all the variables

13r-56

Back to the equation:

-(13r-56)



We get rid of parentheses

16r-13r+56-8=0

We add all the numbers together, and all the variables

3r+48=0

We move all terms containing r to the left, all other terms to the right

3r=-48

r=-48/3

r=-16

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