2(8u+2)=3(2u-12)

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Solution for 2(8u+2)=3(2u-12) equation: 



2(8u+2)=3(2u-12)

We move all terms to the left:

2(8u+2)-(3(2u-12))=0

We multiply parentheses

16u-(3(2u-12))+4=0



We calculate terms in parentheses: -(3(2u-12)), so:

3(2u-12)

We multiply parentheses

6u-36

Back to the equation:

-(6u-36)



We get rid of parentheses

16u-6u+36+4=0

We add all the numbers together, and all the variables

10u+40=0

We move all terms containing u to the left, all other terms to the right

10u=-40

u=-40/10

u=-4

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