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2(8x+3)=4(4x+3/2)
We move all terms to the left:
2(8x+3)-(4(4x+3/2))=0
We add all the numbers together, and all the variables
2(8x+3)-(4(+4x+3/2))=0
We multiply parentheses
16x-(4(+4x+3/2))+6=0
We multiply all the terms by the denominator
16x*2))-(4(+4x+3+6*2))=0
We add all the numbers together, and all the variables
16x*2))-(4(4x+15))=0
We add all the numbers together, and all the variables
16x*2))-(4(4x=0
Wy multiply elements
32x^2=0
a = 32; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·32·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{64}=0$
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