2(8y+4)-5(3y-1)=10

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Solution for 2(8y+4)-5(3y-1)=10 equation: 



2(8y+4)-5(3y-1)=10

We move all terms to the left:

2(8y+4)-5(3y-1)-(10)=0

We multiply parentheses

16y-15y+8+5-10=0

We add all the numbers together, and all the variables

y+3=0

We move all terms containing y to the left, all other terms to the right

y=-3

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