2(8y-8)=y-10(2y+2)

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Solution for 2(8y-8)=y-10(2y+2) equation:



2(8y-8)=y-10(2y+2)
We move all terms to the left:
2(8y-8)-(y-10(2y+2))=0
We multiply parentheses
16y-(y-10(2y+2))-16=0
We calculate terms in parentheses: -(y-10(2y+2)), so:
y-10(2y+2)
We multiply parentheses
y-20y-20
We add all the numbers together, and all the variables
-19y-20
Back to the equation:
-(-19y-20)
We get rid of parentheses
16y+19y+20-16=0
We add all the numbers together, and all the variables
35y+4=0
We move all terms containing y to the left, all other terms to the right
35y=-4
y=-4/35
y=-4/35

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