2(8y-8)=y-10(2y+2)

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Solution for 2(8y-8)=y-10(2y+2) equation: 



2(8y-8)=y-10(2y+2)

We move all terms to the left:

2(8y-8)-(y-10(2y+2))=0

We multiply parentheses

16y-(y-10(2y+2))-16=0



We calculate terms in parentheses: -(y-10(2y+2)), so:

y-10(2y+2)

We multiply parentheses

y-20y-20

We add all the numbers together, and all the variables

-19y-20

Back to the equation:

-(-19y-20)



We get rid of parentheses

16y+19y+20-16=0

We add all the numbers together, and all the variables

35y+4=0

We move all terms containing y to the left, all other terms to the right

35y=-4

y=-4/35

y=-4/35

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