2(8z-2)=28

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Solution for 2(8z-2)=28 equation: 



2(8z-2)=28

We move all terms to the left:

2(8z-2)-(28)=0

We multiply parentheses

16z-4-28=0

We add all the numbers together, and all the variables

16z-32=0

We move all terms containing z to the left, all other terms to the right

16z=32

z=32/16

z=2

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