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2(9+6x)-3=9x+3(x+5)
We move all terms to the left:
2(9+6x)-3-(9x+3(x+5))=0
We add all the numbers together, and all the variables
2(6x+9)-(9x+3(x+5))-3=0
We multiply parentheses
12x-(9x+3(x+5))+18-3=0
We calculate terms in parentheses: -(9x+3(x+5)), so:We add all the numbers together, and all the variables
9x+3(x+5)
We multiply parentheses
9x+3x+15
We add all the numbers together, and all the variables
12x+15
Back to the equation:
-(12x+15)
12x-(12x+15)+15=0
We get rid of parentheses
12x-12x-15+15=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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