2(9-2+m)+3=4(m-3)+11+2

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Solution for 2(9-2+m)+3=4(m-3)+11+2 equation: 



2(9-2+m)+3=4(m-3)+11+2

We move all terms to the left:

2(9-2+m)+3-(4(m-3)+11+2)=0

We add all the numbers together, and all the variables

2(m+7)-(4(m-3)+11+2)+3=0

We multiply parentheses

2m-(4(m-3)+11+2)+14+3=0



We calculate terms in parentheses: -(4(m-3)+11+2), so:

4(m-3)+11+2

We add all the numbers together, and all the variables

4(m-3)+13

We multiply parentheses

4m-12+13

We add all the numbers together, and all the variables

4m+1

Back to the equation:

-(4m+1)



We add all the numbers together, and all the variables

2m-(4m+1)+17=0

We get rid of parentheses

2m-4m-1+17=0

We add all the numbers together, and all the variables

-2m+16=0

We move all terms containing m to the left, all other terms to the right

-2m=-16

m=-16/-2

m=+8

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