2(96+2m)=2(80-3m)

Solution for 2(96+2m)=2(80-3m) equation:

2(96+2m)=2(80-3m)

We move all terms to the left:

2(96+2m)-(2(80-3m))=0

We add all the numbers together, and all the variables

2(2m+96)-(2(-3m+80))=0

We multiply parentheses

4m-(2(-3m+80))+192=0


We calculate terms in parentheses: -(2(-3m+80)), so:

2(-3m+80)

We multiply parentheses

-6m+160

Back to the equation:

-(-6m+160)


We get rid of parentheses

4m+6m-160+192=0

We add all the numbers together, and all the variables

10m+32=0

We move all terms containing m to the left, all other terms to the right

10m=-32

m=-32/10

m=-3+1/5