2(96+2m)=80-3m

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Solution for 2(96+2m)=80-3m equation: 



2(96+2m)=80-3m

We move all terms to the left:

2(96+2m)-(80-3m)=0

We add all the numbers together, and all the variables

2(2m+96)-(-3m+80)=0

We multiply parentheses

4m-(-3m+80)+192=0

We get rid of parentheses

4m+3m-80+192=0

We add all the numbers together, and all the variables

7m+112=0

We move all terms containing m to the left, all other terms to the right

7m=-112

m=-112/7

m=-16

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