2(9m-5)=-7(m-8)+9

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Solution for 2(9m-5)=-7(m-8)+9 equation: 



2(9m-5)=-7(m-8)+9

We move all terms to the left:

2(9m-5)-(-7(m-8)+9)=0

We multiply parentheses

18m-(-7(m-8)+9)-10=0



We calculate terms in parentheses: -(-7(m-8)+9), so:

-7(m-8)+9

We multiply parentheses

-7m+56+9

We add all the numbers together, and all the variables

-7m+65

Back to the equation:

-(-7m+65)



We get rid of parentheses

18m+7m-65-10=0

We add all the numbers together, and all the variables

25m-75=0

We move all terms containing m to the left, all other terms to the right

25m=75

m=75/25

m=3

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