2(9m-5)=-7(m-8)+9

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Solution for 2(9m-5)=-7(m-8)+9 equation:



2(9m-5)=-7(m-8)+9
We move all terms to the left:
2(9m-5)-(-7(m-8)+9)=0
We multiply parentheses
18m-(-7(m-8)+9)-10=0
We calculate terms in parentheses: -(-7(m-8)+9), so:
-7(m-8)+9
We multiply parentheses
-7m+56+9
We add all the numbers together, and all the variables
-7m+65
Back to the equation:
-(-7m+65)
We get rid of parentheses
18m+7m-65-10=0
We add all the numbers together, and all the variables
25m-75=0
We move all terms containing m to the left, all other terms to the right
25m=75
m=75/25
m=3

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