2(9n+4)-12=3(2n-4)+20

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Solution for 2(9n+4)-12=3(2n-4)+20 equation:



2(9n+4)-12=3(2n-4)+20
We move all terms to the left:
2(9n+4)-12-(3(2n-4)+20)=0
We multiply parentheses
18n-(3(2n-4)+20)+8-12=0
We calculate terms in parentheses: -(3(2n-4)+20), so:
3(2n-4)+20
We multiply parentheses
6n-12+20
We add all the numbers together, and all the variables
6n+8
Back to the equation:
-(6n+8)
We add all the numbers together, and all the variables
18n-(6n+8)-4=0
We get rid of parentheses
18n-6n-8-4=0
We add all the numbers together, and all the variables
12n-12=0
We move all terms containing n to the left, all other terms to the right
12n=12
n=12/12
n=1

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