2(9n+4)-12=3(2n-4)+20

Solution for 2(9n+4)-12=3(2n-4)+20 equation:

2(9n+4)-12=3(2n-4)+20

We move all terms to the left:

2(9n+4)-12-(3(2n-4)+20)=0

We multiply parentheses

18n-(3(2n-4)+20)+8-12=0


We calculate terms in parentheses: -(3(2n-4)+20), so:

3(2n-4)+20

We multiply parentheses

6n-12+20

We add all the numbers together, and all the variables

6n+8

Back to the equation:

-(6n+8)


We add all the numbers together, and all the variables

18n-(6n+8)-4=0

We get rid of parentheses

18n-6n-8-4=0

We add all the numbers together, and all the variables

12n-12=0

We move all terms containing n to the left, all other terms to the right

12n=12

n=12/12

n=1