2(9x+9)/6=3(2x+4)/2

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Solution for 2(9x+9)/6=3(2x+4)/2 equation: 



2(9x+9)/6=3(2x+4)/2

We move all terms to the left:

2(9x+9)/6-(3(2x+4)/2)=0

We calculate fractions


18x/()+(-(3(2x+4)*6)/()=0



We calculate terms in parentheses: +(-(3(2x+4)*6)/(), so:

-(3(2x+4)*6)/(

We multiply all the terms by the denominator


-(3(2x+4)*6)



We calculate terms in parentheses: -(3(2x+4)*6), so:

3(2x+4)*6

We multiply parentheses

36x+72

Back to the equation:

-(36x+72)



We get rid of parentheses

-36x-72

Back to the equation:

+(-36x-72)



We get rid of parentheses

18x/()-36x-72=0

We multiply all the terms by the denominator


18x-36x*()-72*()=0

We add all the numbers together, and all the variables

18x-36x*()=0

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