2(9x-4)+10(2+5x)=8(5x-9)-7(9+2x)

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Solution for 2(9x-4)+10(2+5x)=8(5x-9)-7(9+2x) equation:



2(9x-4)+10(2+5x)=8(5x-9)-7(9+2x)
We move all terms to the left:
2(9x-4)+10(2+5x)-(8(5x-9)-7(9+2x))=0
We add all the numbers together, and all the variables
2(9x-4)+10(5x+2)-(8(5x-9)-7(2x+9))=0
We multiply parentheses
18x+50x-(8(5x-9)-7(2x+9))-8+20=0
We calculate terms in parentheses: -(8(5x-9)-7(2x+9)), so:
8(5x-9)-7(2x+9)
We multiply parentheses
40x-14x-72-63
We add all the numbers together, and all the variables
26x-135
Back to the equation:
-(26x-135)
We add all the numbers together, and all the variables
68x-(26x-135)+12=0
We get rid of parentheses
68x-26x+135+12=0
We add all the numbers together, and all the variables
42x+147=0
We move all terms containing x to the left, all other terms to the right
42x=-147
x=-147/42
x=-3+1/2

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