2(9z+3)=3(z+7)

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Solution for 2(9z+3)=3(z+7) equation: 



2(9z+3)=3(z+7)

We move all terms to the left:

2(9z+3)-(3(z+7))=0

We multiply parentheses

18z-(3(z+7))+6=0



We calculate terms in parentheses: -(3(z+7)), so:

3(z+7)

We multiply parentheses

3z+21

Back to the equation:

-(3z+21)



We get rid of parentheses

18z-3z-21+6=0

We add all the numbers together, and all the variables

15z-15=0

We move all terms containing z to the left, all other terms to the right

15z=15

z=15/15

z=1

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